Homeschool Guide: These lesson plans are a guide for parents. Content may contain errors — always cross-reference with official exam board specifications.
p4 specific heat capacity
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4 detailed 50-minute lessons with teaching scripts, worked examples, parent guides, and assessment criteria.
Lesson Overview
Total Lessons: 4 Tier: Foundation and Higher Duration: 50 minutes per lesson (200 minutes total) Exam Boards: AQA, Edexcel, OCR, Eduqas, CCEA
Learning Objectives
Explain the key ideas of p4 specific heat capacity
Apply p4 specific heat capacity to exam-style questions
Key vocab to pre-teach: Specific heat capacity (c), Rearranging the equation, Water has a very high SHC
Basic skills: reading the summary notes and answering the practice questions there
Materials & Equipment
Exercise book, coloured pens
Scientific calculator
Ruler
Printed revision notes (link below)
Internet for videos (see Resources)
Lesson 1: Introduction: p4 specific heat capacity
Duration: 50 minutes
Starter Activity (5 minutes)
Quick Recall
Write down everything you already know about p4 specific heat capacity. Then check against the key terms: Specific heat capacity (c), Rearranging the equation, Water has a very high SHC. Use a mini-whiteboard or paper.
Main Content (35 minutes)
Parent/Teacher Guide: Before lesson: Read the script below. Pre-teach key vocab: Specific heat capacity (c), Rearranging the equation, Water has a very high SHC. If stuck: Re-read the revision notes (link above), then break the content into smaller steps. Extension: See the Stretch & Challenge ideas in Lesson 4.
Teaching Script (35 mins): Mins 0-5 - Hook: "Today: p4 specific heat capacity. By the end you will be able to answer exam questions on it unaided. It connects to the rest of Combined Science (Trilogy) because the ideas here recur across the spec." Mins 5-20 - Direct Instruction: Work through the core ideas below one at a time; after each, ask your student to explain it back in their own words. Mins 20-30 - Guided Practice: Model the worked example together, then let your student attempt the first practice question with guidance. Mins 30-35 - Independent Practice: 2-3 practice questions from Lesson 3 below, with immediate feedback.
First Look
Start with the revision notes summary, then attempt: Foundation Define specific heat capacity and state its unit.
Plenary (5 minutes)
Check Out
Your student states one thing they learned and one question they still have about p4 specific heat capacity.
Lesson 2: Core Concepts: p4 specific heat capacity
Duration: 50 minutes
Starter Activity (5 minutes)
Review Previous Lesson
Quick recap: write 3 key points from Lesson 1 on p4 specific heat capacity. Check them against the notes below.
Main Content (35 minutes)
Specific heat capacity (c): The amount of energy needed to change the temperature of 1 kg of a substance by 1 °C. Measured in joules per kilogram per degree Celsius (J/kg°C).
Key idea: Different substances need different amounts of energy to change their temperature by the same amount. A substance with a high SHC takes a lot of energy to heat up, but also stores a lot of energy.
Rearranging the equation: c = ΔE / (m x ΔT). m = ΔE / (c x ΔT). ΔT = ΔE / (m x c).
Water has a very high SHC: — it takes 4200 J to heat 1 kg of water by 1 °C. This means water stores a lot of thermal energy, which is why it is used in central heating systems and as a coolant.
Aim: To measure the specific heat capacity of a material (typically a metal block).
Water is ideal for central heating systems: because its high specific heat capacity means it can store a large amount of thermal energy and release it slowly as it flows through radiators. This makes it an effective heat transfer fluid.
Term
Meaning
Example
Water
4200
Needs a lot of energy to heat up — stores lots of energy
Aluminium
900
Heats up quickly with less energy
Iron
450
Heats up even more quickly
Copper
385
Heats up quickly — good for saucepans
Lead
130
Very easy to change temperature
Oil
~2000
Less than water, heats up faster than water
Practice (10 minutes)
Q: Foundation Define specific heat capacity and state its unit.
Answer: The specific heat capacity of a substance is the amount of energy needed to change the temperature of 1 kg of the substance by 1 °C. The unit is J/kg°C (joules per kilogram per degree Celsius).
Plenary (5 minutes)
Explain Back
Your student teaches the key points back to you without looking. Fill any gaps immediately.
Lesson 3: Application: p4 specific heat capacity
Duration: 50 minutes
Starter Activity (5 minutes)
Quick Recall
Recall the key terms: Specific heat capacity (c), Rearranging the equation, Water has a very high SHC. Define each in one sentence.
Main Content (35 minutes)
Parent/Teacher Guide: Let your student attempt each question alone first, then compare with the model answer. Award method marks for correct working even if the final answer is wrong.
Q1: Foundation Define specific heat capacity and state its unit.
Answer: The specific heat capacity of a substance is the amount of energy needed to change the temperature of 1 kg of the substance by 1 °C. The unit is J/kg°C (joules per kilogram per degree Celsius).
Q2: Foundation Calculate the energy needed to heat 3 kg of water from 15 °C to 85 °C. c = 4200 J/kg°C.
Answer: ΔE = m x c x ΔT = 3 x 4200 x (85 - 15) = 3 x 4200 x 70 = 882 000 J = 882 kJ.
Q3: Foundation Explain why water is used in central heating systems rather than oil.
Answer: Water has a higher SHC (4200 J/kg°C) than oil (~2000 J/kg°C). This means water stores more thermal energy per kg for each degree of temperature rise. Water can therefore carry more energy from the boiler to the radiators and release it over a longer time, making it more effective for heating.
Q4: Higher A 1.5 kg block of iron (c = 450 J/kg°C) is heated from 20 °C to 120 °C. Calculate the energy supplied.
Answer: ΔE = m x c x ΔT = 1.5 x 450 x (120 - 20) = 1.5 x 450 x 100 = 67 500 J = 67.5 kJ.
Q5: Higher In a required practical, a 0.4 kg metal block is heated by a 10 V, 2 A heater for 7 minutes. The temperature rises by 35 °C. Calculate the SHC. Explain why the true SHC may be different from your calculated value.
Answer: E = V x I x t = 10 x 2 x (7 x 60) = 10 x 2 x 420 = 8400 J. c = E / (m x ΔT) = 8400 / (0.4 x 35) = 8400 / 14 = 600 J/kg°C. The true SHC may be different because some energy is lost to the surroundings (not all heat goes into the block), so the calculated SHC is higher than the true value. Also, the thermometer may not read the true average temperature of the block.
Plenary (5 minutes)
Error Review
Review any questions answered incorrectly. Identify whether the error was knowledge, method, or reading the question.
Lesson 4: Exam Practice: p4 specific heat capacity
Duration: 50 minutes
Starter Activity (5 minutes)
Command Words
Review what these command words require: state (one point), describe (say what happens), explain (say why), compare (both sides), evaluate (judgement).
Main Content (35 minutes)
Extended Answer
Extended question: Extended Answer 6 marks: Describe how you would investigate the specific heat capacity of a metal block in the laboratory. Explain your method and evaluate the main sources of error and how they affect the result. <div class="
Method: Measure the mass of the metal block using a balance. Wrap the block in insulation to reduce heat loss. Insert an immersion heater and a thermometer into the holes in the block. Record the initial temperature. Connect the immersion heater to a joulemeter (or use a voltmeter, ammeter and stopwatch and calculate E = V × I × t). Switch on the heater for a set time (e.g. 10 minutes). Record the final temperature and the total energy supplied. Calculate the SHC using c = E ÷ (m × ΔT). Sources of error: (1) Heat loss to the surroundings — not all the electrical energy goes into heating the block; some is dissipated to the thermal store of the air and insulation. This means the calculated SHC is higher than the true value because less energy actually heats the block than the joulemeter records. (2) The thermometer may not be in good thermal contact with the block, so the measured temperature change may be inaccurate. (3) Heat may not be distributed evenly through the block, creating hot spots near the heater. To improve: use thicker insulation, allow time for heat to distribute before reading the final temperature, and use a smaller temperature rise to reduce heat loss. Mark scheme
Exam Tips: Always convert mass to kilograms before using the equation — a common mistake is using grams. | ΔT is the temperature change , not the final temperature. Calculate ΔT = T_final minus T_initial. | In the required practical, if using E = VIt, make sure you convert time to seconds . | If your calculated SHC seems too high, it is likely because of heat loss to the surroundings — not all the energy goes into heating the block. | When comparing substances: high SHC = hard to heat, stores lots of energy; low SHC = easy to heat, stores less energy . | The water SHC value (4200 J/kg°C) comes up frequently — memorise it.
Common Errors: Watch Out! 1. Wrong: A high SHC means something gets very hot quickly Correct: A high SHC means a substance needs MORE energy to change its temperature — it heats up slowly and stores lots of thermal energy 2. Wrong: Temperature and thermal energy are the same thing Correct: Temperature measures how hot something is (°C), while thermal energy depends on mass, SHC and temperature change — a large bath of warm water has more thermal energy than a small cup of boiling water 3. Wrong: You can use mass in grams directly in the SHC equation Correct: Mass must always be in kilograms — 200 g must be converted to 0.2 kg before using ΔE = mcΔT
AO3 - Reasoning & Interpretation: Analysis and Evaluation A student heats two blocks with the same immersion heater for the same time. Block A is aluminium (mass 1.0 kg, c = 900 J/kg°C) and Block B is iron (mass 1.0 kg, c = 450 J/kg°C). The heater supplies 18 000 J of energy to each block. Both blocks start at 20 °C. (a) Calculate the temperature rise and final temperature of each block. (b) The student's results show that the aluminium block only rises by 16 °C instead of the calculated value. Explain why the actual temperature rise is less than expected. (c) A student claims "Iron must store more thermal energy than aluminium because it reaches a higher temperature." Evaluate this claim. Answers: (a) Block A: ΔT = 18 000 ÷
Stretch & Challenge (Grade 8-9):
Synoptic links: explain how p4 specific heat capacity connects to another Combined Science (Trilogy) topic you have studied
Real-world: research one real-world use or example of p4 specific heat capacity
Critical: "What are the limitations of the models used in p4 specific heat capacity?"
Plenary (5 minutes)
Assessment Criteria
Got it: Confident explanation + correct worked examples
Getting there: Main points OK, needs support with detail
Not yet: Confused on key concepts - re-run Lesson 2
Homework & Consolidation
Consolidation: Re-answer any Lesson 3 practice questions answered incorrectly (20 mins)
Retrieval: Write flashcards for the key terms: Specific heat capacity (c), Rearranging the equation, Water has a very high SHC (10 mins)
Exam practice: One past-paper question on p4 specific heat capacity from the board websites (15 mins)
Extension: Explain p4 specific heat capacity to someone else in your own words (10 mins)