Homeschool Guide: These lesson plans are a guide for parents. Content may contain errors — always cross-reference with official exam board specifications.
alcohols carboxylic acids and polymers
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4 detailed 50-minute lessons with teaching scripts, worked examples, parent guides, and assessment criteria.
Lesson Overview
Total Lessons: 4 Tier: Foundation and Higher Duration: 50 minutes per lesson (200 minutes total) Exam Boards: AQA, Edexcel, OCR, Eduqas, CCEA
Learning Objectives
Explain the key ideas of alcohols carboxylic acids and polymers
Apply alcohols carboxylic acids and polymers to exam-style questions
Key vocab to pre-teach: Alcohols, Carboxylic acids, Addition polymers
Basic skills: reading the summary notes and answering the practice questions there
Materials & Equipment
Exercise book, coloured pens
Scientific calculator
Ruler
Printed revision notes (link below)
Internet for videos (see Resources)
Lesson 1: Introduction: alcohols carboxylic acids and polymers
Duration: 50 minutes
Starter Activity (5 minutes)
Quick Recall
Write down everything you already know about alcohols carboxylic acids and polymers. Then check against the key terms: Alcohols, Carboxylic acids, Addition polymers. Use a mini-whiteboard or paper.
Main Content (35 minutes)
Parent/Teacher Guide: Before lesson: Read the script below. Pre-teach key vocab: Alcohols, Carboxylic acids, Addition polymers. If stuck: Re-read the revision notes (link above), then break the content into smaller steps. Extension: See the Stretch & Challenge ideas in Lesson 4.
Teaching Script (35 mins): Mins 0-5 - Hook: "Today: alcohols carboxylic acids and polymers. By the end you will be able to answer exam questions on it unaided. It connects to the rest of Combined Science (Trilogy) because the ideas here recur across the spec." Mins 5-20 - Direct Instruction: Work through the core ideas below one at a time; after each, ask your student to explain it back in their own words. Mins 20-30 - Guided Practice: Model the worked example together, then let your student attempt the first practice question with guidance. Mins 30-35 - Independent Practice: 2-3 practice questions from Lesson 3 below, with immediate feedback.
First Look
Start with the revision notes summary, then attempt: Name the functional group present in alcohols and give one use of ethanol.
Plenary (5 minutes)
Check Out
Your student states one thing they learned and one question they still have about alcohols carboxylic acids and polymers.
Lesson 2: Core Concepts: alcohols carboxylic acids and polymers
Duration: 50 minutes
Starter Activity (5 minutes)
Review Previous Lesson
Quick recap: write 3 key points from Lesson 1 on alcohols carboxylic acids and polymers. Check them against the notes below.
Main Content (35 minutes)
Alcohols: are a homologous series with the functional group –OH (hydroxyl group). Their general formula is CₙH₂ₙ₊₁OH. They are used as solvents, fuels and in alcoholic drinks.
Alcohols undergo three key reactions: combustion , oxidation and reaction with sodium .
Alcohols are oxidised to form carboxylic acids . Oxidising agents such as acidified potassium dichromate(VI) are used. Ethanol oxidises to ethanoic acid.
Carboxylic acids: have the functional group –COOH . They dissolve in water to give acidic solutions (pH below 7). They are weak acids because they only partially ionise in water.
Carboxylic acids are weak acids because they partially ionise in water. This means fewer H⁺ ions are released compared to strong acids like HCl, so their reactions are less vigorous.
An ester is formed when an alcohol reacts with a carboxylic acid . Water is also produced. Esters have pleasant fruity smells and are used in perfumes and flavourings.
Term
Meaning
Example
Methanol
CH₃OH
Industrial solvent, chemical feedstock
Ethanol
C₂H₅OH
Alcoholic drinks, fuel, solvent
Propanol
C₃H₇OH
Solvent, cleaning agent
Methanoic acid
HCOOH
Found in ant stings
Ethanoic acid
CH₃COOH
Vinegar (dilute solution)
Propanoic acid
C₂H₅COOH
Food preservative
Ethene (C₂H₄)
Polyethene (polythene)
Carrier bags, bottles
Propene (C₃H₆)
Polypropene (polypropylene)
Rope, crates, car parts
Practice (10 minutes)
Q: Name the functional group present in alcohols and give one use of ethanol.
Answer: The functional group in alcohols is the hydroxyl group (–OH) . Ethanol is used as a fuel, a solvent, or in alcoholic drinks.
Plenary (5 minutes)
Explain Back
Your student teaches the key points back to you without looking. Fill any gaps immediately.
Lesson 3: Application: alcohols carboxylic acids and polymers
Duration: 50 minutes
Starter Activity (5 minutes)
Quick Recall
Recall the key terms: Alcohols, Carboxylic acids, Addition polymers. Define each in one sentence.
Main Content (35 minutes)
Parent/Teacher Guide: Let your student attempt each question alone first, then compare with the model answer. Award method marks for correct working even if the final answer is wrong.
Q1: Name the functional group present in alcohols and give one use of ethanol.
Answer: The functional group in alcohols is the hydroxyl group (–OH) . Ethanol is used as a fuel, a solvent, or in alcoholic drinks.
Q2: Write a balanced symbol equation for the complete combustion of ethanol.
Answer: C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
Q3: Explain why carboxylic acids are described as weak acids.
Answer: Carboxylic acids are weak acids because they partially ionise in water. Only a small proportion of acid molecules dissociate to release H⁺ ions, so their reactions are less vigorous than strong acids.
Q4: Higher Write a word equation for the formation of an ester from propanol and ethanoic acid. State the conditions needed.
Answer: Propanol + Ethanoic acid → Propyl ethanoate + Water. An acid catalyst (e.g. concentrated sulfuric acid) is needed, and the mixture is heated.
Q5: Describe how addition polymers are formed from alkene monomers. Use ethene and polyethene as an example.
Answer: Addition polymerisation involves opening the C=C double bond in each alkene monomer. The monomers join together in a long chain. For ethene: the C=C double bond opens, and the molecules link to form polyethene, (—CH₂—CH₂—)ₙ. No other substance is produced.
Q6: Higher Compare addition polymerisation and condensation polymerisation.
Answer: Addition polymerisation uses one type of monomer (alkenes); condensation uses two different monomers. Addition produces no by-product; condensation produces water. Addition polymers form C—C bonds from opened C=C; condensation polymers form ester linkages.
Plenary (5 minutes)
Error Review
Review any questions answered incorrectly. Identify whether the error was knowledge, method, or reading the question.
Lesson 4: Exam Practice: alcohols carboxylic acids and polymers
Duration: 50 minutes
Starter Activity (5 minutes)
Command Words
Review what these command words require: state (one point), describe (say what happens), explain (say why), compare (both sides), evaluate (judgement).
Main Content (35 minutes)
Extended Answer
Extended question: Extended Answer 6 marks: Compare addition polymerisation and condensation polymerisation, including the monomers involved, the products, and the type of bond formed. Give an example of each. <div class="
Addition polymerisation uses a single type of monomer — alkenes with a C=C double bond. The double bond opens and the monomers join together in a long chain. No other substance is produced as a by-product. The bond formed between monomers is a C—C single bond from the opened C=C double bond. An example is the polymerisation of ethene to form polyethene: n C₂H₄ → (—CH₂—CH₂—)ₙ. Condensation polymerisation uses two different types of monomer. For polyesters, one monomer is a diol (with two –OH groups) and the other is a dicarboxylic acid (with two –COOH groups). Each time the monomers join, a molecule of water is lost as a by-product. The bond formed between monomers is an ester linkage (—COO—). An example is the formation of a polyester from a diol and a dicarboxylic acid: diol + dicarboxylic acid → polyester + water. The key differences are: addition uses one monomer type and produces no by-product, while condensation uses two monomer types and produces water. Mark scheme: 1 mark for addition monomer type (alkenes, single type); 1 mark for addition mechanism (C=C opens, no by-product); 1 mark for addition example; 1 mark for condensation monomer types (diol + dicarboxylic acid); 1 m
Exam Tips: When writing equations for alcohol combustion, always balance C first, then H, then O | For polymerisation questions: addition polymers come from alkenes (double bond opens), condensation polymers come from two different monomers (water lost) | Carboxylic acids are WEAK acids — they partially ionise, unlike HCl which is a strong acid that fully ionises | When drawing polymer repeating units, open the C=C double bond and show the bonds going outside the brackets | Remember: alcohols + sodium → less vigorous than water + sodium (ethanol is less acidic than water)
Common Errors: Watch Out! 1. Wrong: Carboxylic acids are strong acids because they are acids Correct: Carboxylic acids are WEAK acids — they only partially ionise in water, releasing fewer H⁺ ions than strong acids like HCl 2. Wrong: Addition polymers produce water as a by-product Correct: Addition polymers produce NO by-product — the C=C double bond simply opens and monomers join together. Only CONDENSATION polymers produce water 3. Wrong: Oxidation of ethanol produces water and carbon dioxide Correct: Oxidation of ethanol produces ETHANOIC ACID and water — combustion produces CO₂ and water, but oxidation with an oxidising agent is different from combustion 4. Wrong: A polymer and its monomer have the sam
AO3 - Reasoning & Interpretation: Methanol: 0.32 g burned, temperature rise = 24°C, energy per mole = 1008 kJ/mol | Ethanol: 0.46 g burned, temperature rise = 24°C, energy per mole = 840 kJ/mol | Propanol: 0.60 g burned, temperature rise = 24°C, energy per mole = 840 kJ/mol | Butanol: 0.74 g burned, temperature rise = 24°C, energy per mole = 840 kJ/mol
Stretch & Challenge (Grade 8-9):
Synoptic links: explain how alcohols carboxylic acids and polymers connects to another Combined Science (Trilogy) topic you have studied
Real-world: research one real-world use or example of alcohols carboxylic acids and polymers
Critical: "What are the limitations of the models used in alcohols carboxylic acids and polymers?"
Plenary (5 minutes)
Assessment Criteria
Got it: Confident explanation + correct worked examples
Getting there: Main points OK, needs support with detail
Not yet: Confused on key concepts - re-run Lesson 2
Homework & Consolidation
Consolidation: Re-answer any Lesson 3 practice questions answered incorrectly (20 mins)
Retrieval: Write flashcards for the key terms: Alcohols, Carboxylic acids, Addition polymers (10 mins)
Exam practice: One past-paper question on alcohols carboxylic acids and polymers from the board websites (15 mins)
Extension: Explain alcohols carboxylic acids and polymers to someone else in your own words (10 mins)